Factorize 3x^5 - 48x

3x^5 - 48x
= 3x(x^4 - 16), taking 3x common
= 3x[(x^2)^2 - 4^2]
= 3x[(x^2 - 4)(x^2 + 4)], since A^2 - B^2 = (A - B)(A + B)
= 3x[(x^2 - 2^2)(x^2 + 4)]
= 3x[(x - 2)(x + 2)(x^2 + 4)], using, again, A^2 - B^2 = (A - B)(A + B)
= 3x(x - 2)(x + 2)(x^2 + 4) Ans.