Using the property A^(M*N)=(A^M)^N,we get
a^6 - b^6 = (a^3)^2 - (b^3) ^ 2
= (a^3 - b^3)(a^3 + b^3) , applying A^2 - B^2 = (A - B)(A + B)
= [(a - b)(a^2 + ab + b^2)][(a + b)(a^2 - ab + b^2)] , using A^3 - B^3 = (A - B)(A^2 + AB + B^2)
= (a - b) (a + b) (a^2 + ab + b^2) (a^2 - ab + b^2) Ans.
The last step was arrived at by using associativity and commutativity of multiplication.
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